Generalization of PICASSO POINT.
Let ABC be a triangle, A'B'C' the antipodal triangle of ABC (=circumcevian triangle of O) and D a point.
Let A"B"C" be the circumcevian triangle of D with respect A'B'C' (ie A" is the other than A' intersection of A'D with the circumcircle etc)
Denote:
N1,N2,N3 the NPC centers of the triangles A"BC, B"CA, C"AB.
The four NPC centers N, N1,N2,N3 are concyclic.
Which is the center, General Picasso Point, of the circle ?
APH, 17 January 2012
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This is the midpoint of DH.
Francisco Javier García Capitán
17 January 2012
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