euclid 4119
Σάββατο 29 Ιανουαρίου 2022
Πέμπτη 27 Ιανουαρίου 2022
TWO POINTS ON THE MCCAY CUBIC
X(mccay1) = (name pending)
Barycentrics (pending)See Antreas Hatzipolakis and César Lozada, euclid 3664.
X(mccay1) lies on the cubics K003, K762, K849, K854 and these lines: { }
X(mccay2) = (name pending)
Barycentrics (pending)See Antreas Hatzipolakis and César Lozada, euclid 4073 and Bernard Gibert, Q175, Q177 .
X(mccay2) lies on the cubic K003, these curves Q018, Q98, Q157, Q175, Q177 and these lines: { }
Εγγραφή σε:
Αναρτήσεις (Atom)
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Let ABC be a triangle. Denote: (N1),(N2), (N3) = the NPCs of IBC, ICA, IAB, resp. (12), (13) = the reflections of (N1) in BI, CI, resp. ... -
Theorem 1. Let ABC be an equilateral triangle and P a point. The Euler lines of the triangles PBC,PCA,PAB are concurent.Denote the point ...
