To construct triangle ABC if are given the radii r_1, r_2, r_3, defined
as follows: Let Da be a point on BC such that inradius of ABDa = inradius of ACDa := r_1. Similarly r_2, r_3
Let ABC be the triangle, Da, Db, Dc, three points on BC,CA,AB, resp. such that: inradius of ABDa = inradius of ACDa = r_1, and similarly Db,Dc and AHa := h_a, BH_b : = h_b, CH_c := h_c the three altitudes of ABC and r its inradius.
By this Theorem we have:
h_a = 2(r_1)^2 / (2r_1 - r) ==>
1/h_a = (2r_1 - r) / 2(r_1)^2
1/h_b = (2r_2 - r) / 2(r_2)^2
1/h_c = (2r_3 - r) / 2(r_3)^2
1/r = 1/h_a + 1/h_b + 1/h_c
1/r = [(2r_1 - r) / 2(r_1)^2 ] + [(2r_2 - r) / 2(r_2)^2] + [(2r_3 - r) / 2(r_3)^2]
r^2(1/(r_1)^2 + 1/(r_2)^2 + 1/(r_3)^2) - 2r(1/r_1 + 1/r_2 + 1/r_3) + 2 = 0
==> r is known ==> h_a, h_b, h_c are known (from the formulae above).
So we have to construct triangle ABC whose the three altitudes are known.
It's an easy problem.