Let ABC be a triangle and HaHbHc the orthic triangle.
Denote:
(Na) = the reflection of the circle (N,NA) in AHa
(Nb) = the reflection of the circle (N,NB) in BHb
(Nc) = the reflection of the circle (N,NC) in CHc
1. The circles (Na),(Nb),(Nc) are concurrent at a point P
2. The triangles HaHbHc, NaNbNc are perspective at a point Q.
Antreas P. Hatzipolakis, 22 Febr. 2013
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