Παρασκευή 10 Ιουλίου 2026

ETC

X(72801) = X(10)X(79)∩X(35)X(502)

Barycentrics    -((b+c)^2*(a^2+a*b+b^2-c^2)*(-a^2+b^2-a*c-c^2)) : :

Francisco Javier García Capitán, euclid 9871.

X(72801) liea on circumconics with center X(i) for i in {4092, 21709} and these lines: {10, 79}, {35, 502}, {42, 1989}, {171, 13486}, {210, 8013}, {226, 21054}, {3214, 56843}, {3701, 6757}, {4518, 30690}, {4705, 15475}, {6186, 7110}, {6742, 14844}, {7100, 59305}, {9140, 33097}, {20488, 69298}, {20499, 33078}, {21077, 21682}, {21089, 32936}, {21674, 52382}, {21686, 52390}, {21717, 63171}, {21729, 71630}, {23901, 33081}, {23927, 61358}, {23930, 69300}, {27577, 56847}, {36815, 52449}, {41504, 69545}, {43682, 70316}, {56191, 56844}

X(72801) = intersection, other than A, B, C, of the circumconics: {{A,B,C,X(10),X(6535)}, {A,B,C,X(12),X(210)}, {A,B,C,X(37),X(21873)}, {A,B,C,X(42),X(4705)}, {A,B,C,X(86),X(4683)}, {A,B,C,X(226),X(4024)}, {A,B,C,X(321),X(6543)}, {A,B,C,X(430),X(6175)}, {A,B,C,X(502),X(6058)}, {A,B,C,X(523),X(55925)}}
X(72801) = pole of tripolar of X(16755) with respect to the dual conic of Wallace hyperbola
X(72801) = barycentric product X(i)*X(j) for these (i, j): {10, 8818}, {12, 7110}, {37, 6757}, {79, 594}, {210, 43682}, {756, 30690}, {1089, 2160}, {1500, 20565}, {1577, 56193}, {1826, 52388}, {2166, 4053}, {2171, 52344}, {2321, 52382}, {3695, 64834}, {3952, 55236}, {4024, 6742}, {4705, 15455}, {6057, 52374}, {6186, 28654}, {6358, 7073}, {6535, 52393}, {7140, 52381}, {8013, 60139}, {21675, 57710}, {30713, 69470}, {43082, 68819}, {53008, 63171}, {55209, 58289}
X(72801) = barycentric quotient X(i)/X(j) for these (i, j): {10, 34016}, {12, 17095}, {37, 56934}, {42, 40214}, {79, 1509}, {181, 2003}, {210, 56440}, {213, 17104}, {523, 16755}, {594, 319}, {756, 3219}, {762, 3678}, {872, 2174}, {1089, 33939}, {1334, 35193}, {1500, 35}, {1962, 17190}, {2160, 757}, {2171, 1442}, {2643, 7202}, {3124, 53542}, {3952, 55235}, {4024, 4467}, {4036, 18160}, {4079, 2605}, {4705, 14838}, {6057, 42033}, {6186, 593}, {6358, 52421}, {6535, 3969}, {6742, 4610}, {6757, 274}, {7064, 52405}, {7073, 2185}, {7110, 261}, {7140, 52412}, {8013, 3578}, {8029, 21141}, {8606, 65568}, {8736, 7282}, {8818, 86}, {15455, 4623}, {21043, 8287}, {21794, 7279}, {21816, 3647}, {21824, 7266}, {21833, 2611}, {30690, 873}, {43682, 57785}, {52344, 52379}, {52374, 552}, {52375, 763}, {52382, 1434}, {52388, 17206}, {52393, 6628}, {55236, 7192}, {56193, 662}, {58289, 55210}, {59179, 30581}, {69470, 1412}
X(72801) = trilinear product X(i)*X(j) for these (i, j): {12, 7073}, {37, 8818}, {42, 6757}, {79, 756}, {181, 52344}, {210, 52382}, {523, 56193}, {594, 2160}, {762, 52393}, {872, 20565}, {1018, 55236}, {1089, 6186}, {1334, 43682}, {1500, 30690}, {1824, 52388}, {1989, 4053}, {2171, 7110}, {3701, 69470}, {3949, 64834}, {4079, 15455}, {4705, 6742}, {6057, 52372}, {6535, 52375}, {6538, 59179}, {7100, 7140}, {8013, 57419}, {8606, 56285}, {11060, 61410}, {21816, 60139}, {52390, 53008}
X(72801) = trilinear quotient X(i)/X(j) for these (i, j): {10, 56934}, {12, 1442}, {35, 756}, {37, 40214}, {42, 17104}, {60, 7073}, {79, 757}, {81, 8818}, {86, 6757}, {110, 56193}, {115, 7202}, {181, 1399}, {210, 35193}, {261, 52344}, {319, 1089}, {321, 34016}, {323, 4053}, {593, 2160}, {594, 3219}, {763, 52393}, {849, 6186}, {873, 20565}, {1014, 52382}, {1019, 55236}, {1213, 17190}, {1334, 35192}, {1408, 69470}, {1434, 43682}, {1444, 52388}, {1500, 2174}, {1509, 30690}, {1577, 16755}, {2003, 2171}, {2185, 7110}, {2321, 56440}, {2605, 4705}, {2611, 21043}, {2643, 53542}, {3647, 8013}, {3678, 6535}, {3690, 52408}, {4024, 14838}, {4033, 55235}, {4036, 4467}, {4092, 53524}, {4420, 6057}, {4610, 15455}, {6198, 7140}, {6358, 17095}, {6538, 59140}, {6742, 52935}, {7186, 7237}, {7266, 21054}, {7282, 56285}, {7341, 52372}, {7799, 61410}, {11107, 53008}, {16585, 21675}, {16718, 21018}, {17454, 21816}, {18160, 52623}, {20982, 21833}, {23226, 55230}, {28654, 33939}, {30593, 52569}, {34388, 52421}, {52558, 57419}
X(72801) = {X(i),X(j)}-harmonic conjugate of X(k) for these (i,j,k): {7073, 56193, 42}


X(72802) = X(51)X(21354)∩X(418)X(8612)

Barycentrics    a^2*(a^2-b^2-c^2)*(a^2*b^2-b^4+a^2*c^2+2*b^2*c^2-c^4)^2*(a^8*b^4-4*a^6*b^6+6*a^4*b^8-4*a^2*b^10+b^12+a^10*c^2-2*a^6*b^4*c^2-4*a^4*b^6*c^2+9*a^2*b^8*c^2-4*b^10*c^2-4*a^8*c^4+2*a^4*b^4*c^4-4*a^2*b^6*c^4+6*b^8*c^4+6*a^6*c^6-2*a^2*b^4*c^6-4*b^6*c^6-4*a^4*c^8+b^4*c^8+a^2*c^10)*(a^10*b^2-4*a^8*b^4+6*a^6*b^6-4*a^4*b^8+a^2*b^10+a^8*c^4-2*a^6*b^2*c^4+2*a^4*b^4*c^4-2*a^2*b^6*c^4+b^8*c^4-4*a^6*c^6-4*a^4*b^2*c^6-4*a^2*b^4*c^6-4*b^6*c^6+6*a^4*c^8+9*a^2*b^2*c^8+6*b^4*c^8-4*a^2*c^10-4*b^2*c^10+c^12) : :

Francisco Javier García Capitán, euclid 9871.

X(72802) lies on these lines: {51, 21354}, {216, 34985}, {418, 8612}, {467, 1972}, {2055, 3484}

Χ(72802) = intersection, other than A, B, C, of the circumconics: {{A,B,C,X(216),X(324)}, {A,B,C,X(418),X(23607)}, {A,B,C,X(2055),X(33664)}}
Χ(72802) = barycentric quotient X(i)/X(j) for these (i, j): {46394, 2055}, {61378, 8613}, {62260, 56298}
Χ(72802) = trilinear quotient X(i)/X(j) for these (i, j): {56298, 62259}


Δευτέρα 1 Ιουνίου 2026

CYCLOLOGIC

Let ABC be a triangle

Denote

1. Oa, Ob, Oc = the circumcenters of HBC, HCA, HAB, resp.

ABC, OaObOc are cyclologic, since Oa, Ob, Oc are the reflections of O in BC,CA,AB, resp.
Cyclologic center (OaObOc, ABC) = antigonal conjugate of O = X(265)

2. Sa, Sb, Sc = the X(54) of HBC, HCA, HAB, resp.

ABC,SaSbSc are cyclologic

Cyclologic centers?

Παρασκευή 22 Μαΐου 2026

G - Orthologic

Let ABC be a triangle, P = G = X(2) and Q a point on the Euler line.

Denote:

Bc, Cb = the orthogonal projections of B, C on GC, GB, resp.

Qa = same to Q point of the triangle ABcCb.
Similarly Qb, Qc.

ABC, QaQbQc are orthologic.

For Q = G = X(2)
Orthologic center (ABC, QaQbQc) = G* = ?
Orthologic center (QaQbQc, ABC) = G** = ?

For Q = X(3) = O:
Orthologic center (ABC, QaQbQc) = O* = X(36889)
Orthologic center (QaQbQc, ABC) = O** = X(1352)
Euclid 9541

Q = H = X(4)
Orthologic center (ABC, QaQbQc) = H* = X(3)= O
Orthologic center (QaQbQc, ABC) = H** = ?

Q = N = X(5)
Orthologic center (ABC, QaQbqc) = N* = ?
Orthologic center (QaQbQc, ABC) = N** = ?

The locus of the orthologic center (QaQbQc, ABC) = Q**, as Q moves on the Euler line, is a line.
(OQ/OH = O**Q**/O**H**)

Locus of the orthologic center (ABC, QaQbQc) ?

H - Orthologic

Let ABC be a triangle, P = H = X(4) and Q a point on the Euler line.

Denote:

Bc, Cb = the orthogonal projections of B, C on HC, HB, resp.

Qa = same to Q point of the triangle ABcCb.
Similarly Qb, Qc.

ABC, QaQbQc are orthologic.

For Q = G = X(2)
Orthologic center (ABC, QaQbQc) = G* = ?
Orthologic center (QaQbQc, ABC) = G** = G of orthic = X(51)

For Q = X(3) = O:
Orthologic centers = X(4) = H

Q = H = X(4)
Orthologic center (ABC, QaQbQc) = H* = X(3) = O
Orthologic center (QaQbQc, ABC) = H** = ?

For Q = N = X(5)
Orthologic center (ABC, QaQbQc) = N* = ?
Orthologic center (QaQbQc, ABC) = N** = ?

The locus of the orthologic center (QaQbQc, ABC) = Q**, as Q moves on the Euler line, is a line. (The line {4,51})
(OQ/OH = O**Q**/O**H**)

Locus of the orthologic center (ABC, QaQbQc) ?

O - Orthologic

Let ABC be a triangle, P = O = X(3) and Q a point on the Euler line.

Denote:

Bc, Cb = the orthogonal projections of B, C on OC, OB, resp.

Qa = same to Q point of the triangle ABcCb.
Similarly Qb, Qc.

ABC, QaQbQc are orthologic.

Orthologic center (QaQbQc, ABC) = Q

For Q = G = X(2)
Orthologic center (ABC, QaQbQc) = G* = ?

For Q = X(3) = O:
Orthologic center (ABC, QaQbQc) = O* = X(72422) = X(2)X(9291)∩X(4)X(290)

For Q = H = X(4)
Orthologic center (ABC, QaQbQc) = H* = ?

For Q = N = X(5)
Orthologic center (ABC, QaQbQc) = N* = ?

Locus:
The locus of the orthologic center (ABC, QaQbQc) = Q*, as Q moves on the Euler line, is a CIRCLE

Πέμπτη 21 Μαΐου 2026

LOCI

Let ABC be a triangle and P a point.

Denote:
Bc, Cb = the orthogonal projections of B, C on PC, PB, resp.

A' = the other than A intersection the circumcircles of ABC and ABcCb
Similarly B',C'

La, B, Lc = Euler lines of A'BC, B'CA, C'AB, resp.

1. Which is the locus of P such that ABC, A'B'C' are orthologic?
O lies on the locus
Orthologic center (ABC, A'B'C') = (3) = O
Orthologic center ( A'B'C', ABC) = Χ(20)

2. Which is the locus of P such that the parallels to La,Lb, Lc through A, B, C,resp, are concurrent?
O lies on the locus.
.

ETC

X(72801) = X(10)X(79)∩X(35)X(502) Barycentrics    -((b+c)^2*(a^2+a*b+b^2-c^2)*(-a^2+b^2-a*c-c^2)) : : Francisco Javier García Capitán,...