The radical axis of the circumcircles of ABC and OQP intersect the line OP at P'. P' is the inverse of P wrt circumcircle of ABC
APH, Comment in Romantics of Geometry problem
Let ABC be a triangle, P = G = X(2) and Q a point on the Euler line. Denote: Bc, Cb = the orthogonal projections of B, C on GC, GB, resp. ...
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