Πέμπτη 30 Ιανουαρίου 2025

INVERSE IN THE CIRCUMCIRCLE

Let ABC be a triangle, O the circumcenter, P a point different to O and Q a point not lying on the OP line.
The radical axis of the circumcircles of ABC and OQP intersect the line OP at P'. P' is the inverse of P wrt circumcircle of ABC
APH, Comment in Romantics of Geometry problem

Δεν υπάρχουν σχόλια:

Δημοσίευση σχολίου

z

X(72392) = X(110)X(3164)∩X(112)X(3168) Barycentrics    (a^10*b^2 - 2*a^8*b^4 + 2*a^6*b^6 - 2*a^4*b^8 + a^2*b^10 - a^10*c^2 - 2*a^8*b^2*c^...