The radical axis of the circumcircles of ABC and OQP intersect the line OP at P'. P' is the inverse of P wrt circumcircle of ABC
APH, Comment in Romantics of Geometry problem
X(73027) = (name pending) Barycentrics (3*a^6-4*a^4*b^2-a^2*b^4+2*b^6-4*a^4*c^2+7*a^2*b^2*c^2-2*b^4*c^2-a^2*c^4-2*b^2*c^4+2*c^6)*(8*a^1...
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