Orthic Version
Let ABC be a triangle, HaHbHc the orthic triangle and P a point.
Denote:
Pa, Pb, Pc = same to P points of AHbHc, BHcHa, CHaHb, resp.
HaHbHc, PaPbPc are circumcyclologic
Cyclologic center (HaHbHc, PaPbPc = ? (on the circumcircle of HaHbHc = NPC)
Cyclologic center (PaPbPc, HaHbHc) = ? (on the circumcircle of PaPbPc)
[Ercole Suppa]
cyclologic center (HaHbHc, PaPbPc) = Poncelet point(isogonal conjugate(P))
cyclologic center (PaPbPc, HaHbHc) = orthoassociate(isogonal conjugate(circumcircleInverse(P)))
