Πέμπτη 27 Ιανουαρίου 2022

TWO POINTS ON THE MCCAY CUBIC

X(mccay1) = (name pending)

Barycentrics    (pending)

See Antreas Hatzipolakis and César Lozada, euclid 3664.

X(mccay1) lies on the cubics K003, K762, K849, K854 and these lines: { }


X(mccay2) = (name pending)

Barycentrics    (pending)

See Antreas Hatzipolakis and César Lozada, euclid 4073 and Bernard Gibert, Q175, Q177 .

X(mccay2) lies on the cubic K003, these curves Q018, Q98, Q157, Q175, Q177 and these lines: { }


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G - Orthologic

Let ABC be a triangle, P = G = X(2) and Q a point on the Euler line. Denote: Bc, Cb = the orthogonal projections of B, C on GC, GB, resp. ...