Σάββατο 14 Σεπτεμβρίου 2013

PRIZE (Re: ORTHOCENTER - REFLECTIONS - CONCURRENT CIRCLES)

[APH]: In fact we can take any point P (instead of H) and any points O1,O2,O3 on the circumcircles of PBC,PCA,PAB, resp.

Then the circumcircles of the triangles

AO2O3, BO3O1, CO1O2

are concurrent.

Anopolis #850

For a proof I offer the book:

R. G. SANGER: SYNTHETIC PROJECTIVE GEOMETRY (1939)

APH

1 σχόλιο:

X(63254), X(63255)

X(63254) = (name pending) Barycentrics    a^2*(a^2 - b^2 - c^2)*(a^16*b^2 - 8*a^14*b^4 + 28*a^12*b^6 - 56*a^10*b^8 + 70*a^8*b^10 - 56*a^6*b...