Σάββατο 14 Σεπτεμβρίου 2013

PRIZE (Re: ORTHOCENTER - REFLECTIONS - CONCURRENT CIRCLES)

[APH]: In fact we can take any point P (instead of H) and any points O1,O2,O3 on the circumcircles of PBC,PCA,PAB, resp.

Then the circumcircles of the triangles

AO2O3, BO3O1, CO1O2

are concurrent.

Anopolis #850

For a proof I offer the book:

R. G. SANGER: SYNTHETIC PROJECTIVE GEOMETRY (1939)

APH

1 σχόλιο:

CYCLOLOGIC

Let ABC be a triangle Denote 1. Oa, Ob, Oc = the circumcenters of HBC, HCA, HAB, resp. ABC, OaObOc are cyclologic, since Oa, Ob, Oc...