Σάββατο 14 Σεπτεμβρίου 2013

PRIZE (Re: ORTHOCENTER - REFLECTIONS - CONCURRENT CIRCLES)

[APH]: In fact we can take any point P (instead of H) and any points O1,O2,O3 on the circumcircles of PBC,PCA,PAB, resp.

Then the circumcircles of the triangles

AO2O3, BO3O1, CO1O2

are concurrent.

Anopolis #850

For a proof I offer the book:

R. G. SANGER: SYNTHETIC PROJECTIVE GEOMETRY (1939)

APH

1 σχόλιο:

CORR

X(73009) = X(4)X(1854)∩X(46)X(80) Barycentrics    (2*a^4-a^3*b-a^2*b^2+a*b^3-b^4-a^3*c+2*a^2*b*c-a*b^2*c-a^2*c^2-a*b*c^2+2*b^2*c^2+a*c^3-c^...