[APH]:
In fact we can take any point P (instead of H) and any points
O1,O2,O3 on the circumcircles of PBC,PCA,PAB, resp.
Then the circumcircles of the triangles
AO2O3, BO3O1, CO1O2
are concurrent.
Anopolis #850
For a proof I offer the book:
R. G. SANGER: SYNTHETIC PROJECTIVE GEOMETRY (1939)
APH
Here is a proof : http://www.artofproblemsolving.com/Forum/blog.php?u=118092&b=95655
ΑπάντησηΔιαγραφήKind Regards,
Ivan