Τρίτη 23 Απριλίου 2013

PERSPECTIVE

Let ABC be a triangle, A'B'C' the antipedal triangle of P = O and Oa, Ob, Oc the circumcenters of OB'C', OC'A', OA'B'. resp.

Denote:

Ab = ObOa /\ OcA

Ac = OcOa /\ ObA

Bc = OcOb /\ OaB

Ba = OaOb /\ OcB

Ca = OaOc /\ ObC

Cb = ObOc /\ OaC

The triangles OaObOc, Triangle A*B*C* bounded by (AbAc, BcBa, CaCb) are perspective (??).

Locus of P ??

Antreas P. Hatzipolakis, Anopolis #156

-

Δεν υπάρχουν σχόλια:

Δημοσίευση σχολίου

Εγγραφή σε: Σχόλια ανάρτησης (Atom)

ETC1

X(73131) = X(4)X(94)∩X(526)X(20304) Barycentrics    a^2*(a^16*b^4-7*a^14*b^6+21*a^12*b^8-35*a^10*b^10+35*a^8*b^12-21*a^6*b^14+7*a^4*b^16-a^...

  • EUCLID 4404
  • ANOPOLIS CIRCLE
    Let ABC be a triangle. Denote: (N1),(N2), (N3) = the NPCs of IBC, ICA, IAB, resp. (12), (13) = the reflections of (N1) in BI, CI, resp. ...
  • HOMOTHETIC TRIANGLES and EULER LINES
    Theorem 1. Let ABC be an equilateral triangle and P a point. The Euler lines of the triangles PBC,PCA,PAB are concurent.Denote the point ...