Τρίτη 29 Ιανουαρίου 2013

CONICS CENTERED AT O

Let ABC be a triangle and r1,r2,r3 three not equal line segments.

Denote:

a1 = the circle centered at A with radius r1. Similarly ....

a1b2 = the radical axis of the circles a1 and b2. Similarly .....

Six Radical centers:

(a1,b2,c3), (a1,b3,c2), (a2,b3,c1), (a2,b1,c3), (a3,b1,c2), (a3,b2,c1)

Six other points of concurrent radical axes:

(a1b2,b3c1,c2a3), (a1b3,b2c1,c3a2), (a2b3,b1c2,c3a1), (a2b1,b3c2,c1a3), (a3b1,b2c3,c1a2),(a3b2,b1c3,c2a1)

The 12gon has opposite sides parallel and equal. It is inscribed on a conic centered at the circumcenter O = radical center of (a1,b1,c1) and (a2,b2,c2) and (a3,b3,c3)

Antreas P. Hatzipolakis. 29 Jan. 2013

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X(72934) = (name pending) Barycentrics    a ((a^2+b^2-c^2) (a^2-b^2+c^2) (a^9 b^3-a^8 b^4-3 a^7 b^5+3 a^6 b^6+3 a^5 b^7-3 a^4 b^8-a^3 b^9+...