Παρασκευή 22 Μαΐου 2026

O - Orthologic

Let ABC be a triangle, P = O = X(3) and Q a point on the Euler line.

Denote:

Bc, Cb = the orthogonal projections of B, C on OC, OB, resp.

Qa = same to Q point of the triangle ABcCb.
Similarly Qb, Qc.

ABC, QaQbQc are orthologic.

Orthologic center (QaQbQc, ABC) = Q

For Q = X(3) = O:
Orthologic center (ABC, OaObOc) = X(72422) = X(2)X(9291)∩X(4)X(290)

For Q = G = X(2) or Q = H = X(4) or Q = N = X(5)
Orthologic center (ABC, QaQbQc) ?

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G - Orthologic

Let ABC be a triangle, P = G = X(2) and Q a point on the Euler line. Denote: Bc, Cb = the orthogonal projections of B, C on GC, GB, resp. ...

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