Denote:
PQa = the isogonal conjugate of P wrt QBC
PQb = the isogonal conjugate of P wrt QCA
PQc = the isogonal conjugate of P wrt QAB
QPa = the isogonal conjugate of Q wrt PBC
QPb = the isogonal conjugate of Q wrt PCA
QPc = the isogonal conjugate of Q wrt PAB
Apq = PQaQPa /\ BC
Bpq = PQbQPb /\ CA
Cpq = PQcQPc /\ AB
Conjecture: The points Apq, Bpq, Cpq are collinear.
Let R be another point. We have the lines (if the conjecture is true):
ApqBpqCpq, AqrBqrCqr, ArpBrpCrp.
Are they concurrent? Do they bound a triangle in perspective with ABC?
Antreas P. Hatzipolakis, 18 May 2013
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