Παρασκευή 10 Φεβρουαρίου 2012

Perspective


Let ABC be a triangle, A'B'C' the orthic triangle, A1B1C1 the cevian triangle of G and A2B2C2 the circumcevian triangle of G with respect A1B1C1.


Denote:

A* = A2O /\ A'N

B* = B2O /\ B'N

C* = C2O /\ C'N

The triangles ABC, A*B*C* are perspective (?)
(perspector on the Euler line?)

Variation:

A** = A2N /\ A'O

B** = B2N /\ B'O

C** = C2N /\ C'O

Are the triangles:

ABC, A**B**C**

A*B*C*, A**B**C**

perspective?

APH, 10 February 2012

Δεν υπάρχουν σχόλια:

Δημοσίευση σχολίου

z

X(72392) = X(110)X(3164)∩X(112)X(3168) Barycentrics    (a^10*b^2 - 2*a^8*b^4 + 2*a^6*b^6 - 2*a^4*b^8 + a^2*b^10 - a^10*c^2 - 2*a^8*b^2*c^...