Πέμπτη 30 Ιανουαρίου 2025

INVERSE IN THE CIRCUMCIRCLE

Let ABC be a triangle, O the circumcenter, P a point different to O and Q a point not lying on the OP line.
The radical axis of the circumcircles of ABC and OQP intersect the line OP at P'. P' is the inverse of P wrt circumcircle of ABC
APH, Comment in Romantics of Geometry problem

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X(71995) = X(2)X(187)∩X(3)X(3734) Barycentrics    2*a^4 - 3*a^2*b^2 - 3*a^2*c^2 - 2*b^2*c^2 : : X(71995) = 3 X[2] + X[14907], 3 X[183]...