Σάββατο 14 Σεπτεμβρίου 2013

PRIZE (Re: ORTHOCENTER - REFLECTIONS - CONCURRENT CIRCLES)

[APH]: In fact we can take any point P (instead of H) and any points O1,O2,O3 on the circumcircles of PBC,PCA,PAB, resp.

Then the circumcircles of the triangles

AO2O3, BO3O1, CO1O2

are concurrent.

Anopolis #850

For a proof I offer the book:

R. G. SANGER: SYNTHETIC PROJECTIVE GEOMETRY (1939)

APH

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ETC

X(69262) = EULER LINE INTERCEPT OF X(51)X(53415) Barycentrics    2 a^6-a^4 b^2-2 a^2 b^4+b^6-a^4 c^2+12 a^2 b^2 c^2-b^4 c^2-2 a^2 c^4-b^...